What is the integral of 1/(-sqrt(x)) ?

The integral of 1/(-sqrt(x)) is -2sqrt(x)+C

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integral of 1/(-sqrt(x))

\int \frac{1}{- x} d x

- 2 x + C

Solution steps

\int \frac{1}{- x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{x} d x

Apply the Power Rule

: 2 x^{\frac{1}{2}}

= - 2 x^{\frac{1}{2}}

Apply radical rule:

= - 2 x

Add a constant to the solution

= - 2 x + C

\int \frac{2 x + 3}{x ^{2} + 3 x - 5} d x

\int ln (\frac{1}{x}) d x

\frac{d y}{d t} = (a \cdot 2) - \frac{y}{20} 2, y (0) = 0

\frac{d y}{d x} = x (4 x + 5)^{\frac{1}{3}}

What is the integral of 1/(-sqrt(x)) ?
The integral of 1/(-sqrt(x)) is -2sqrt(x)+C