What is the integral of (x^{1.7}+7x^{2.5}) ?

The integral of (x^{1.7}+7x^{2.5}) is 0.37037…x^{2.7}+2x^{3.5}+C

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integral of (x^{1.7}+7x^{2.5})

\int (x^{1.7} + 7 x^{2.5}) d x

0.37037 \dots x^{2.7} + 2 x^{3.5} + C

Solution steps

\int x^{1.7} + 7 x^{2.5} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{1.7} d x + \int 7 x^{2.5} d x

\int x^{1.7} d x = 0.37037 \dots x^{2.7}

\int 7 x^{2.5} d x = 2 x^{3.5}

= 0.37037 \dots x^{2.7} + 2 x^{3.5}

Add a constant to the solution

= 0.37037 \dots x^{2.7} + 2 x^{3.5} + C

x \to 2 + lim (\frac{x ^{2}}{x - 2})

f (t) = \frac{1}{2 t + 3}

n = 0 \sum \infty 6 (- 1)^{n} n x^{n}

sin (2 θ) cos (θ)

x \to - 2 + lim (3 x + 6 - 6)

What is the integral of (x^{1.7}+7x^{2.5}) ?
The integral of (x^{1.7}+7x^{2.5}) is 0.37037…x^{2.7}+2x^{3.5}+C