What is laplacetransform 4sin(5t) ?

The answer to laplacetransform 4sin(5t) is (20)/(s^2+25)

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laplacetransform 4sin(5t)

laplace transform

4 sin (5 t)

\frac{20}{s ^{2} + 25}

Solution steps

L {4 sin (5 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 4 L {sin (5 t)}

L {sin (5 t)} : \frac{5}{s ^{2} + 25}

= 4 \cdot \frac{5}{s ^{2} + 25}

Refine

4 \frac{5}{s ^{2} + 25} : \frac{20}{s ^{2} + 25}

= \frac{20}{s ^{2} + 25}

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What is laplacetransform 4sin(5t) ?
The answer to laplacetransform 4sin(5t) is (20)/(s^2+25)