What is the limit as x approaches-1-of 1/((x+1)^2) ?

The limit as x approaches-1-of 1/((x+1)^2) is infinity

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limit as x approaches-1-of 1/((x+1)^2)

x \to - 1 - lim (\frac{1}{( x + 1 ) ^{2}})

\infty

Solution steps

x \to - 1 - lim (\frac{1}{( x + 1 ) ^{2}})

For

x

approaching

- 1

from the left

, x < - 1 \Rightarrow (x + 1)^{2} > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

\int_{0}^{\infty} 5^{- x} d x

\int sec^{4} (x) d x

f (t) = t^{4}

(1436.53) \cdot (1.01395)^{t}

n = 0 \sum \infty 4 (\frac{2}{3})^{n - 1}

What is the limit as x approaches-1-of 1/((x+1)^2) ?
The limit as x approaches-1-of 1/((x+1)^2) is infinity