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Popular >

integral of 4^x

Solution

\int 4^{x} d x

Solution

\frac{2 ^{2 x - 1}}{ln ( 2 )} + C

Solution steps

\int 4^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= \frac{4 ^{x}}{ln ( 4 )}

Simplify

\frac{4 ^{x}}{ln ( 4 )} : \frac{2 ^{2 x - 1}}{ln ( 2 )}

= \frac{2 ^{2 x - 1}}{ln ( 2 )}

Add a constant to the solution

= \frac{2 ^{2 x - 1}}{ln ( 2 )} + C

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Frequently Asked Questions (FAQ)

What is the integral of 4^x ?
The integral of 4^x is (2^{2x-1})/(ln(2))+C