What is the solution for xdx+ydy=0 ?

The solution for xdx+ydy=0 is y=sqrt(-x^2+c_{1)},y=-sqrt(-x^2+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

xdx+ydy=0

x d x + y d y = 0

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

Solution steps

x d x + y d y = 0

Solve separable ODE:

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

\frac{d}{d x} (\frac{4 x ^{4} - 2 x}{4 x ^{4} + 2 x})

\int (\frac{x ^{2} + 4 x - 4}{x}) d x

4 x (x^{2} - 4)

\frac{\partial}{\partial x} (7 y - y^{3} - 4 x^{2} y)

y^{5} y^{^{'}} = - 2 cos (π x)

What is the solution for xdx+ydy=0 ?
The solution for xdx+ydy=0 is y=sqrt(-x^2+c_{1)},y=-sqrt(-x^2+c_{1)}