What is the solution for yln(x)ln(y)dx+dy=0 ?

The solution for yln(x)ln(y)dx+dy=0 is y=e^{e^{x+c_{1}}x^{-x}}

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yln(x)ln(y)dx+dy=0

y ln (x) ln (y) d x + d y = 0

y = e^{e^{x + c_{1}} x^{- x}}

Solution steps

y ln (x) ln (y) d x + d y = 0

Solve separable ODE:

y = e^{e^{x + c_{1}} x^{- x}}

y = e^{e^{x + c_{1}} x^{- x}}

\int \frac{2 ^{x}}{3 ^{x}} d x

\frac{d}{d x} (6 x cos (x^{2}))

\int_{1}^{e} \frac{x ^{2} + 1}{x} d x

y^{^{''}} = - 25 y

\int_{0}^{1} (x^{2} - x) d x

What is the solution for yln(x)ln(y)dx+dy=0 ?
The solution for yln(x)ln(y)dx+dy=0 is y=e^{e^{x+c_{1}}x^{-x}}