What is the slope of (1,-1/2),(-2,-7/2) ?

The slope of (1,-1/2),(-2,-7/2) is m=1

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slope of (1,-1/2),(-2,-7/2)

slope

(1, - \frac{1}{2}), (- 2, - \frac{7}{2})

m = 1

Solution steps

Slope between two points: Slope

= \frac{y _{2} - y _{1}}{x _{2} - x _{1}}

(x_{1}, y_{1}) = (1, - \frac{1}{2}), (x_{2}, y_{2}) = (- 2, - \frac{7}{2})

m = \frac{- \frac{7}{2} - ( - \frac{1}{2} )}{- 2 - 1}

Refine

m = 1

\int_{0}^{\frac{π}{2}} x^{3} cos (2 x) d x

\frac{d}{d x} (\frac{tan ( 3 x ^{3} + x ^{2} )}{e ^{x}})^{3}

x \to 2 lim (- x^{2} + 2 x - 6)

\int \frac{1}{a - x ^{2}} d x

x^{3} + 12 x^{2} + 54 x + 14

What is the slope of (1,-1/2),(-2,-7/2) ?
The slope of (1,-1/2),(-2,-7/2) is m=1