What is the integral of (6x^3+5x^2-46x-39)/(x^2-9) ?

The integral of (6x^3+5x^2-46x-39)/(x^2-9) is 3x^2+5x-ln| x/3+1|+ln| x/3-1|+4ln|x^2-9|-27+C

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integral of (6x^3+5x^2-46x-39)/(x^2-9)

\int \frac{6 x ^{3} + 5 x ^{2} - 46 x - 39}{x ^{2} - 9} d x

3 x^{2} + 5 x - ln \frac{x}{3} + 1 + ln \frac{x}{3} - 1 + 4 ln x^{2} - 9 - 27 + C

Solution steps

\int \frac{6 x ^{3} + 5 x ^{2} - 46 x - 39}{x ^{2} - 9} d x

Expand

\frac{6 x ^{3} + 5 x ^{2} - 46 x - 39}{x ^{2} - 9} : \frac{6 x ^{3}}{x ^{2} - 9} + \frac{5 x ^{2}}{x ^{2} - 9} - \frac{46 x}{x ^{2} - 9} - \frac{39}{x ^{2} - 9}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{6 x ^{3}}{x ^{2} - 9} d x + \int \frac{5 x ^{2}}{x ^{2} - 9} d x - \int \frac{46 x}{x ^{2} - 9} d x - \int \frac{39}{x ^{2} - 9} d x

\int \frac{6 x ^{3}}{x ^{2} - 9} d x = 3 (x^{2} - 9 + 9 ln x^{2} - 9)

\int \frac{5 x ^{2}}{x ^{2} - 9} d x = - 15 (\frac{1}{2} ln \frac{x}{3} + 1 - \frac{1}{2} ln \frac{x}{3} - 1 - \frac{x}{3})

\int \frac{46 x}{x ^{2} - 9} d x = 23 ln x^{2} - 9

\int \frac{39}{x ^{2} - 9} d x = - 13 (\frac{1}{2} ln \frac{x}{3} + 1 - \frac{1}{2} ln \frac{x}{3} - 1)

= 3 (x^{2} - 9 + 9 ln x^{2} - 9) - 15 (\frac{1}{2} ln \frac{x}{3} + 1 - \frac{1}{2} ln \frac{x}{3} - 1 - \frac{x}{3}) - 23 ln x^{2} - 9 - (- 13 (\frac{1}{2} ln \frac{x}{3} + 1 - \frac{1}{2} ln \frac{x}{3} - 1))

Simplify

3 (x^{2} - 9 + 9 ln x^{2} - 9) - 15 (\frac{1}{2} ln \frac{x}{3} + 1 - \frac{1}{2} ln \frac{x}{3} - 1 - \frac{x}{3}) - 23 ln x^{2} - 9 - (- 13 (\frac{1}{2} ln \frac{x}{3} + 1 - \frac{1}{2} ln \frac{x}{3} - 1)) : 3 x^{2} + 5 x - ln \frac{x}{3} + 1 + ln \frac{x}{3} - 1 + 4 ln x^{2} - 9 - 27

= 3 x^{2} + 5 x - ln \frac{x}{3} + 1 + ln \frac{x}{3} - 1 + 4 ln x^{2} - 9 - 27

Add a constant to the solution

= 3 x^{2} + 5 x - ln \frac{x}{3} + 1 + ln \frac{x}{3} - 1 + 4 ln x^{2} - 9 - 27 + C

3 x d y - 2 y d x = 0

\int (x - \frac{1}{x})^{3} d x

\int \frac{1}{( x - 3 ) ^{2} + 3} d x

x \to - 10 lim (7)

\int (y cos (x y)) d x

What is the integral of (6x^3+5x^2-46x-39)/(x^2-9) ?
The integral of (6x^3+5x^2-46x-39)/(x^2-9) is 3x^2+5x-ln| x/3+1|+ln| x/3-1|+4ln|x^2-9|-27+C