What is the derivative of 5ln(4x^2) ?

The derivative of 5ln(4x^2) is (10)/x

What is the first derivative of 5ln(4x^2) ?

The first derivative of 5ln(4x^2) is (10)/x

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\frac{d}{d x} (5 ln (4 x^{2}))

\frac{10}{x}

Solution steps

\frac{d}{d x} (5 ln (4 x^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (ln (4 x^{2}))

Apply the chain rule:

\frac{1}{4 x ^{2}} \frac{d}{d x} (4 x^{2})

= \frac{1}{4 x ^{2}} \frac{d}{d x} (4 x^{2})

\frac{d}{d x} (4 x^{2}) = 8 x

= 5 \cdot \frac{1}{4 x ^{2}} \cdot 8 x

Simplify

5 \cdot \frac{1}{4 x ^{2}} \cdot 8 x : \frac{10}{x}

= \frac{10}{x}

x^{8} + y^{7} = 9

y^{^{'}} + 3 x y^{3} = 0

f (x) = \frac{x + 3}{x - 3}

\int_{- 1}^{2} 3 x 4 x^{2} - 2 d x

x \to 0 - lim (\frac{1}{e ^{x} - 1})

What is the derivative of 5ln(4x^2) ?
The derivative of 5ln(4x^2) is (10)/x
What is the first derivative of 5ln(4x^2) ?
The first derivative of 5ln(4x^2) is (10)/x