What is the integral of 0.815xe^{-0.3x} ?

The integral of 0.815xe^{-0.3x} is 9.05555…(-0.3e^{-0.3x}x-e^{-0.3x})+C

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integral of 0.815xe^{-0.3x}

\int 0.815 x e^{- 0.3 x} d x

9.05555 \dots (- 0.3 e^{- 0.3 x} x - e^{- 0.3 x}) + C

Solution steps

\int 0.815 x e^{- 0.3 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 0.815 \cdot \int x e^{- 0.3 x} d x

Apply u-substitution

: \int \frac{10 e ^{u} u}{0.9} d u

= 0.815 \cdot \int \frac{10 e ^{u} u}{0.9} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 0.815 \cdot \frac{10}{0.9} \cdot \int e^{u} u d u

Simplify

= 0.815 \cdot 11.11111 \dots \cdot \int e^{u} u d u

Apply Integration By Parts

: e^{u} u - \int e^{u} d u

= 0.815 \cdot 11.11111 \dots (e^{u} u - \int e^{u} d u)

\int e^{u} d u = e^{u}

= 0.815 \cdot 11.11111 \dots (e^{u} u - e^{u})

Substitute back

u = - 0.3 x

= 0.815 \cdot 11.11111 \dots (e^{- 0.3 x} (- 0.3 x) - e^{- 0.3 x})

Simplify

= 9.05555 \dots (- 0.3 e^{- 0.3 x} x - e^{- 0.3 x})

Add a constant to the solution

= 9.05555 \dots (- 0.3 e^{- 0.3 x} x - e^{- 0.3 x}) + C

\frac{d}{d x} (x^{2} (x^{2} + 5)^{2})

\frac{d}{d t} (e^{- s t})

\frac{d}{d x} (x cos (5 x))

x \to 1 lim (9 - 4 x^{2})

x = 6 y^{2}, x = 4 + 5 y^{2}

What is the integral of 0.815xe^{-0.3x} ?
The integral of 0.815xe^{-0.3x} is 9.05555…(-0.3e^{-0.3x}x-e^{-0.3x})+C