What is the tangent of f(x)=((x+3))/(2x+1),\at x=-1 ?

The tangent of f(x)=((x+3))/(2x+1),\at x=-1 is y=-5x-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=((x+3))/(2x+1),\at x=-1

tangent of

f (x) = \frac{( x + 3 )}{2 x + 1}, at x = - 1

y = - 5 x - 7

Solution steps

Find the tangent point:

(- 1, - 2)

Find the slope of

f (x) = \frac{x + 3}{2 x + 1} : \frac{df ( x )}{d x} = - \frac{5}{( 2 x + 1 ) ^{2}}

Compute the slope of

f (x) = \frac{x + 3}{2 x + 1}

x = - 1 : m = - 5

Find the line with slope m=

- 5

and passing through

(- 1, - 2) : y = - 5 x - 7

y = - 5 x - 7

x \to 2 lim (\frac{1}{∣ x - 2 ∣})

\int \frac{7 x ^{3} - 1}{x ^{2}} d x

\frac{\partial}{\partial x} (e^{x} sec^{2} (y))

f (x) = \frac{2 x}{x ^{2} + 9}

\int I n^{2} x d x

What is the tangent of f(x)=((x+3))/(2x+1),\at x=-1 ?
The tangent of f(x)=((x+3))/(2x+1),\at x=-1 is y=-5x-7