What is the derivative of 5sec(x-2x) ?

The derivative of 5sec(x-2x) is 5sec(x)tan(x)-2

What is the first derivative of 5sec(x-2x) ?

The first derivative of 5sec(x-2x) is 5sec(x)tan(x)-2

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\frac{d}{d x} (5 sec (x) - 2 x)

5 sec (x) tan (x) - 2

Solution steps

\frac{d}{d x} (5 sec (x) - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 sec (x)) - \frac{d}{d x} (2 x)

\frac{d}{d x} (5 sec (x)) = 5 sec (x) tan (x)

\frac{d}{d x} (2 x) = 2

= 5 sec (x) tan (x) - 2

(- 1.2) (3.4)

\frac{d}{d x} ((3 x^{2})^{2 x})

\int \frac{5 x - 4}{8 x - 5 x ^{2} + 9} d x

\int_{\frac{1}{3}}^{5} 8 x ln (3 x) d x

\frac{d}{d x} (ln (sin (x^{2})))

What is the derivative of 5sec(x-2x) ?
The derivative of 5sec(x-2x) is 5sec(x)tan(x)-2
What is the first derivative of 5sec(x-2x) ?
The first derivative of 5sec(x-2x) is 5sec(x)tan(x)-2