What is area y=x^3-3x^2-27x+14,y=x+14 ?

The answer to area y=x^3-3x^2-27x+14,y=x+14 is 2099/4

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area y=x^3-3x^2-27x+14,y=x+14

area

y = x^{3} - 3 x^{2} - 27 x + 14, y = x + 14

\frac{2099}{4}

Decimal Notation

524.75

Solution steps

Apply the area formula:

\int_{- 4}^{7} x^{3} - 3 x^{2} - 27 x + 14 - (x + 14) d x

Solve

\int_{- 4}^{7} x^{3} - 3 x^{2} - 27 x + 14 - (x + 14) d x : \frac{2099}{4}

The area is:

= \frac{2099}{4}

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What is area y=x^3-3x^2-27x+14,y=x+14 ?
The answer to area y=x^3-3x^2-27x+14,y=x+14 is 2099/4