What is the integral of 11sin((pit)/(12))+10 ?

The integral of 11sin((pit)/(12))+10 is -(132)/pi cos((pit)/(12))+10t+C

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integral of 11sin((pit)/(12))+10

\int 11 sin (\frac{π t}{12}) + 10 d t

- \frac{132}{π} cos (\frac{π t}{12}) + 10 t + C

Solution steps

\int 11 sin (\frac{π t}{12}) + 10 d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 11 sin (\frac{π t}{12}) d t + \int 10 d t

\int 11 sin (\frac{π t}{12}) d t = - \frac{132}{π} cos (\frac{π t}{12})

\int 10 d t = 10 t

= - \frac{132}{π} cos (\frac{π t}{12}) + 10 t

Add a constant to the solution

= - \frac{132}{π} cos (\frac{π t}{12}) + 10 t + C

n = 0 \sum \infty 0. 5^{n}

y^{^{'}} - \frac{2}{x} y = x^{2} e^{x}

\int \frac{x ^{3} - 3 x ^{2} + 5}{( x - 3 )} d x

x \to 1 lim (\frac{1}{x ^{2} - 1})

\frac{s}{( s - 1 ) ^{2} + 1}

What is the integral of 11sin((pit)/(12))+10 ?
The integral of 11sin((pit)/(12))+10 is -(132)/pi cos((pit)/(12))+10t+C