What is the limit as x approaches-0.001 of 4x^2+7 ?

The limit as x approaches-0.001 of 4x^2+7 is 7.000004

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches-0.001 of 4x^2+7

x \to - 0.001 lim (4 x^{2} + 7)

7.000004

Solution steps

x \to - 0.001 lim (4 x^{2} + 7)

Plug in the value

x = - 0.001

= 4 (- 0.001)^{2} + 7

Simplify

4 (- 0.001)^{2} + 7 : 7.000004

= 7.000004

\frac{\partial}{\partial x} (4 x^{3} y^{3} - 18 y - x)

\frac{\partial}{\partial y} (9 x sin (y - z))

\int_{- 4}^{- 1} x^{4} d x

\int 20 tan^{6} (x) d x

\frac{d y}{d x} = 2 y (1 - \frac{y}{4})

What is the limit as x approaches-0.001 of 4x^2+7 ?
The limit as x approaches-0.001 of 4x^2+7 is 7.000004