What is the derivative of x^2-8/(x^3) ?

The derivative of x^2-8/(x^3) is 2x+(24)/(x^4)

What is the first derivative of x^2-8/(x^3) ?

The first derivative of x^2-8/(x^3) is 2x+(24)/(x^4)

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Popular >

\frac{d}{d x} (x^{2} - \frac{8}{x ^{3}})

2 x + \frac{24}{x ^{4}}

Solution steps

\frac{d}{d x} (x^{2} - \frac{8}{x ^{3}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (\frac{8}{x ^{3}})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (\frac{8}{x ^{3}}) = - \frac{24}{x ^{4}}

= 2 x - (- \frac{24}{x ^{4}})

Simplify

= 2 x + \frac{24}{x ^{4}}

\frac{d}{d x} (1. 4^{x} - 2.7)

\frac{d}{d x} (x arctan (x) - \frac{1}{2} ln (1 + x^{2}))

\frac{d}{d x} (\frac{x}{n})

\frac{\partial}{\partial x} (- \frac{y}{4 x ^{2} + 9 y ^{2}})

y^{^{'}} = x^{2} y - x^{2} y^{2}, y (0) = 17

What is the derivative of x^2-8/(x^3) ?
The derivative of x^2-8/(x^3) is 2x+(24)/(x^4)
What is the first derivative of x^2-8/(x^3) ?
The first derivative of x^2-8/(x^3) is 2x+(24)/(x^4)