What is the derivative of (2x-7/(3x-2)) ?

The derivative of (2x-7/(3x-2)) is (17)/((3x-2)^2)

What is the first derivative of (2x-7/(3x-2)) ?

The first derivative of (2x-7/(3x-2)) is (17)/((3x-2)^2)

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\frac{d}{d x} (\frac{2 x - 7}{3 x - 2})

\frac{17}{( 3 x - 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 x - 7}{3 x - 2})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x - 7 ) ( 3 x - 2 ) - \frac{d}{d x} ( 3 x - 2 ) ( 2 x - 7 )}{( 3 x - 2 ) ^{2}}

\frac{d}{d x} (2 x - 7) = 2

\frac{d}{d x} (3 x - 2) = 3

= \frac{2 ( 3 x - 2 ) - 3 ( 2 x - 7 )}{( 3 x - 2 ) ^{2}}

Expand

2 (3 x - 2) - 3 (2 x - 7) : 17

= \frac{17}{( 3 x - 2 ) ^{2}}

\int 5 - x d x

\int \frac{e ^{t}}{t} d t

\int e^{- λ x} d x

f (x) = x^{2} - 6

x \to - 1 + lim (\frac{x}{x ^{2} + 1})

What is the derivative of (2x-7/(3x-2)) ?
The derivative of (2x-7/(3x-2)) is (17)/((3x-2)^2)
What is the first derivative of (2x-7/(3x-2)) ?
The first derivative of (2x-7/(3x-2)) is (17)/((3x-2)^2)