What is the derivative of x^3-cos(x) ?

The derivative of x^3-cos(x) is 3x^2+sin(x)

What is the first derivative of x^3-cos(x) ?

The first derivative of x^3-cos(x) is 3x^2+sin(x)

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\frac{d}{d x} (x^{3} - cos (x))

3 x^{2} + sin (x)

Solution steps

\frac{d}{d x} (x^{3} - cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (cos (x))

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (cos (x)) = - sin (x)

= 3 x^{2} - (- sin (x))

Simplify

= 3 x^{2} + sin (x)

\int - 7 sin (x) d x

- \frac{7}{x ^{3}}

y d y = \frac{2}{x} d x

(2 x + 2 x^{- 2} y) d x + (x y - x^{- 1}) d y = 0

\frac{\partial}{\partial y} (6 x - 3 y)

What is the derivative of x^3-cos(x) ?
The derivative of x^3-cos(x) is 3x^2+sin(x)
What is the first derivative of x^3-cos(x) ?
The first derivative of x^3-cos(x) is 3x^2+sin(x)