What is the integral of xln(10x) ?

The integral of xln(10x) is 1/2 x^2ln(10x)-(x^2)/4+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of xln(10x)

\int x ln (10 x) d x

\frac{1}{2} x^{2} ln (10 x) - \frac{x ^{2}}{4} + C

Solution steps

\int x ln (10 x) d x

Apply Integration By Parts

: \frac{1}{2} x^{2} ln (10 x) - \int \frac{x}{2} d x

= \frac{1}{2} x^{2} ln (10 x) - \int \frac{x}{2} d x

\int \frac{x}{2} d x = \frac{x ^{2}}{4}

= \frac{1}{2} x^{2} ln (10 x) - \frac{x ^{2}}{4}

Add a constant to the solution

= \frac{1}{2} x^{2} ln (10 x) - \frac{x ^{2}}{4} + C

\int sec (x) tan (x) - 2 e^{x} d x

\int sin^{5} (2 θ) d θ

\frac{\partial}{\partial x} (5 x^{2} y)

\int 9 cos^{4} (x) d x

(2, 4), (3, 6)

What is the integral of xln(10x) ?
The integral of xln(10x) is 1/2 x^2ln(10x)-(x^2)/4+C