What is the derivative of y=e^{1-x} ?

The derivative of y=e^{1-x} is -e^{1-x}

What is the first derivative of y=e^{1-x} ?

The first derivative of y=e^{1-x} is -e^{1-x}

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derivative of

y = e^{1 - x}

- e^{1 - x}

Solution steps

\frac{d}{d x} (e^{1 - x})

Apply the chain rule:

e^{1 - x} \frac{d}{d x} (1 - x)

= e^{1 - x} \frac{d}{d x} (1 - x)

\frac{d}{d x} (1 - x) = - 1

= e^{1 - x} (- 1)

Simplify

= - e^{1 - x}

\frac{d}{d x} (ln^{2} (3 x))

F (s) = (\frac{2}{s} - \frac{1}{s ^{3}})^{2}

\int (1 + 2 x^{2}) e^{x^{2}} d x

x \to 3 lim (x 13 - x^{2})

\int_{1}^{2} x d x

What is the derivative of y=e^{1-x} ?
The derivative of y=e^{1-x} is -e^{1-x}
What is the first derivative of y=e^{1-x} ?
The first derivative of y=e^{1-x} is -e^{1-x}