What is area (x^2)/(x^3-3x), 1/(x^3-3x),2,11 ?

The answer to area (x^2)/(x^3-3x), 1/(x^3-3x),2,11 is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area (x^2)/(x^3-3x), 1/(x^3-3x),2,11

area

\frac{x ^{2}}{x ^{3} - 3 x}, \frac{1}{x ^{3} - 3 x}, 2, 11

\frac{1}{2} ln (118) + \frac{1}{3} ln (11) - \frac{1}{3} ln (2) - \frac{1}{6} ln (11 + 3) + \frac{1}{6} ln (2 + 3) - \frac{1}{6} ln (11 - 3) + \frac{1}{6} ln (2 - 3)

Decimal Notation

2.15847 \dots

Solution steps

Apply the area formula:

\int_{2}^{11} \frac{x}{x ^{2} - 3} - \frac{1}{x ^{3} - 3 x} d x

Solve

\int_{2}^{11} \frac{x}{x ^{2} - 3} - \frac{1}{x ^{3} - 3 x} d x : \frac{1}{2} ln (118) + \frac{1}{3} ln (11) - \frac{1}{3} ln (2) - \frac{1}{6} ln (11 + 3) + \frac{1}{6} ln (2 + 3) - \frac{1}{6} ln (11 - 3) + \frac{1}{6} ln (2 - 3)

The area is:

= \frac{1}{2} ln (118) + \frac{1}{3} ln (11) - \frac{1}{3} ln (2) - \frac{1}{6} ln (11 + 3) + \frac{1}{6} ln (2 + 3) - \frac{1}{6} ln (11 - 3) + \frac{1}{6} ln (2 - 3)

\frac{d}{d x} (\frac{x e ^{x}}{sin ( x ) + 1})

tan^{2} (3 x)

y = 6 x^{3} ln (5 x)

\frac{x}{2}, 4

\frac{\partial}{\partial x} (yz e^{x z} + 30)

What is area (x^2)/(x^3-3x), 1/(x^3-3x),2,11 ?
The answer to area (x^2)/(x^3-3x), 1/(x^3-3x),2,11 is