What is the integral from-3 to 1 of sqrt(x+3) ?

The integral from-3 to 1 of sqrt(x+3) is 16/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-3 to 1 of sqrt(x+3)

\int_{- 3}^{1} x + 3 d x

\frac{16}{3}

Decimal Notation

5.33333 \dots

Solution steps

\int_{- 3}^{1} x + 3 d x

Apply u-substitution

: \int_{0}^{4} u d u

= \int_{0}^{4} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{4}

= [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{4}

Compute the boundaries:

\frac{16}{3}

= \frac{16}{3}

y = 2 x^{3} - 3 x + 1, (1, 0)

\frac{d}{d x} (- x sin (x) + cos (x))

\int \frac{1}{3 + cos ( x )} d x

\int_{- π}^{π} ∣ sin (x) ∣ d x

y^{^{'}} = (3 x - 2) (30 x + 19)

What is the integral from-3 to 1 of sqrt(x+3) ?
The integral from-3 to 1 of sqrt(x+3) is 16/3