What is the slope ofintercept (-1,0),(0,-2) ?

The slope ofintercept (-1,0),(0,-2) is y=-2x-2

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slope ofintercept (-1,0),(0,-2)

slope intercept

(- 1, 0), (0, - 2)

y = - 2 x - 2

Solution steps

Compute the slope

(- 1, 0), (0, - 2) : m = - 2

Compute the

y

intercept:

b = - 2

Construct the line equation

y = mx + b

where

m = - 2

and

b = - 2

y = - 2 x - 2

(x^{2} + 3 x y + y^{2}) d x - x^{2} d y = 0

cos (x), - \frac{π}{2}

\frac{5}{x}, y = 3 x, y = \frac{1}{3} x

\int_{a}^{b} \frac{1}{x ^{2}} d x

\int_{0}^{2} x^{2} (2 - x)^{2} d x

What is the slope ofintercept (-1,0),(0,-2) ?
The slope ofintercept (-1,0),(0,-2) is y=-2x-2