What is the solution for (dy)/(dx)=(xy+y+x+1)/(xy+2x-y-2) ?

The solution for (dy)/(dx)=(xy+y+x+1)/(xy+2x-y-2) is y=\W(((-1+x)^2)/(e^{-c_{1)-x-1}})-1

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(dy)/(dx)=(xy+y+x+1)/(xy+2x-y-2)

\frac{d y}{d x} = \frac{x y + y + x + 1}{x y + 2 x - y - 2}

y = W (\frac{( - 1 + x ) ^{2}}{e ^{- c_{1} - x - 1}}) - 1

Solution steps

\frac{d y}{d x} = \frac{x y + y + x + 1}{x y + 2 x - y - 2}

Solve separable ODE:

y = W (\frac{( - 1 + x ) ^{2}}{e ^{- c_{1} - x - 1}}) - 1

y = W (\frac{( - 1 + x ) ^{2}}{e ^{- c_{1} - x - 1}}) - 1

\frac{d}{d x} (\frac{x - 4}{- x ^{2} + 4})

\frac{( 2 s + 1 )}{s ^{2} + 2 s + 5}

\int (x^{2} ln (x)) d x

\frac{\partial}{\partial x} (cos^{2} (3 x))

\frac{d y}{d x} + 2 y = x y^{- 2}

What is the solution for (dy)/(dx)=(xy+y+x+1)/(xy+2x-y-2) ?
The solution for (dy)/(dx)=(xy+y+x+1)/(xy+2x-y-2) is y=\W(((-1+x)^2)/(e^{-c_{1)-x-1}})-1