What is (\partial)/(\partial x)(ye^x+xln(z)) ?

The answer to (\partial)/(\partial x)(ye^x+xln(z)) is ye^x+ln(z)

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(\partial)/(\partial x)(ye^x+xln(z))

\frac{\partial}{\partial x} (y e^{x} + x ln (z))

y e^{x} + ln (z)

Solution steps

\frac{\partial}{\partial x} (y e^{x} + x ln (z))

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y e^{x}) + \frac{\partial}{\partial x} (x ln (z))

\frac{\partial}{\partial x} (y e^{x}) = y e^{x}

\frac{\partial}{\partial x} (x ln (z)) = ln (z)

= y e^{x} + ln (z)

t y^{^{'}} = 4 t^{2} - 2 y

y^{^{''}} x = y^{^{'}}

\frac{\partial}{\partial u} (u v^{2} + w^{3})

\frac{\partial}{\partial x} (x^{2} y e^{x y})

\int_{1}^{2} (x + 1) d x

What is (\partial)/(\partial x)(ye^x+xln(z)) ?
The answer to (\partial)/(\partial x)(ye^x+xln(z)) is ye^x+ln(z)