What is (\partial)/(\partial x)(y^6cos(2x)*2) ?

The answer to (\partial)/(\partial x)(y^6cos(2x)*2) is -4y^6sin(2x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(y^6cos(2x)*2)

\frac{\partial}{\partial x} (y^{6} cos (2 x) \cdot 2)

- 4 y^{6} sin (2 x)

Solution steps

\frac{\partial}{\partial x} (y^{6} cos (2 x) \cdot 2)

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{6} \cdot 2 \frac{\partial}{\partial x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{\partial}{\partial x} (2 x)

= - sin (2 x) \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (2 x) = 2

= y^{6} \cdot 2 (- sin (2 x) \cdot 2)

Simplify

= - 4 y^{6} sin (2 x)

\int 15 x e^{- 8 x^{2}} d x

y^{^{''}} - 4 y^{^{'}} = - 4 y

5 x^{2} + 9 y^{2} = 36, (6, 4)

\frac{d}{d x} (\frac{2 x}{ln ( x )})

x \to 0 lim (x - 5)

What is (\partial)/(\partial x)(y^6cos(2x)*2) ?
The answer to (\partial)/(\partial x)(y^6cos(2x)*2) is -4y^6sin(2x)