What is the integral of 2e^x+3sin(x) ?

The integral of 2e^x+3sin(x) is 2e^x-3cos(x)+C

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integral of 2e^x+3sin(x)

\int 2 e^{x} + 3 sin (x) d x

2 e^{x} - 3 cos (x) + C

Solution steps

\int 2 e^{x} + 3 sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 e^{x} d x + \int 3 sin (x) d x

\int 2 e^{x} d x = 2 e^{x}

\int 3 sin (x) d x = - 3 cos (x)

= 2 e^{x} - 3 cos (x)

Add a constant to the solution

= 2 e^{x} - 3 cos (x) + C

\int 5 e^{6} d x

49 y^{^{''}} - 49 y^{^{'}} - 8 y = 0

\frac{\partial}{\partial z} (5 x^{2} - 3 x y^{2} + x yz)

\int (x^{e} + 10 e^{x}) d x

What is the integral of 2e^x+3sin(x) ?
The integral of 2e^x+3sin(x) is 2e^x-3cos(x)+C