What is (\partial)/(\partial x)(y+2-2/x) ?

The answer to (\partial)/(\partial x)(y+2-2/x) is 2/(x^2)

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(\partial)/(\partial x)(y+2-2/x)

\frac{\partial}{\partial x} (y + 2 - \frac{2}{x})

\frac{2}{x ^{2}}

Solution steps

\frac{\partial}{\partial x} (y + 2 - \frac{2}{x})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y) + \frac{\partial}{\partial x} (2) - \frac{\partial}{\partial x} (\frac{2}{x})

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (2) = 0

\frac{\partial}{\partial x} (\frac{2}{x}) = - \frac{2}{x ^{2}}

= 0 + 0 - (- \frac{2}{x ^{2}})

Simplify

= \frac{2}{x ^{2}}

\frac{d}{d x} (3 sin (x) + cos (x))

x \to 8 lim (2 - 6 x^{2} + x^{3})

\int \frac{4 x ^{3} - 3 x}{x} d x

y^{2} y^{^{'}} = y^{3} - 3 x

\int x (3 sec^{2} (x) - 2 tan^{2} (x)) d x

What is (\partial)/(\partial x)(y+2-2/x) ?
The answer to (\partial)/(\partial x)(y+2-2/x) is 2/(x^2)