What is the derivative of x^3y^4 ?

The derivative of x^3y^4 is 3x^2y^4+4y^3(dy)/(dx)x^3

What is the first derivative of x^3y^4 ?

The first derivative of x^3y^4 is 3x^2y^4+4y^3(dy)/(dx)x^3

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\frac{d}{d x} (x^{3} y^{4})

3 x^{2} y^{4} + 4 y^{3} \frac{d y}{d x} x^{3}

Solution steps

\frac{d}{d x} (x^{3} y^{4})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{3}, g = y^{4}

= \frac{d}{d x} (x^{3}) y^{4} + \frac{d}{d x} (y^{4}) x^{3}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (y^{4}) = 4 y^{3} \frac{d y}{d x}

= 3 x^{2} y^{4} + 4 y^{3} \frac{d y}{d x} x^{3}

f (x) = \frac{5 x - 9}{x + 1}, at x = 0

f (x) = \frac{x ^{2}}{x - 1}

\int 4 x 1 - x^{2} d x

\frac{d}{d x} (\frac{24}{( 1 - x ) ^{4}})

\frac{d}{d x} (\frac{- 1}{x ^{3}})

What is the derivative of x^3y^4 ?
The derivative of x^3y^4 is 3x^2y^4+4y^3(dy)/(dx)x^3
What is the first derivative of x^3y^4 ?
The first derivative of x^3y^4 is 3x^2y^4+4y^3(dy)/(dx)x^3