What is the derivative of-3x^{-2} ?

The derivative of-3x^{-2} is 6/(x^3)

What is the first derivative of-3x^{-2} ?

The first derivative of-3x^{-2} is 6/(x^3)

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\frac{d}{d x} (- 3 x^{- 2})

\frac{6}{x ^{3}}

Solution steps

\frac{d}{d x} (- 3 x^{- 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 3 (- 2 x^{- 2 - 1})

Simplify

- 3 (- 2 x^{- 2 - 1}) : \frac{6}{x ^{3}}

= \frac{6}{x ^{3}}

\frac{\partial}{\partial x} (e^{x yz})

- 3 x^{2} + 4 x + 4

x \to 1 - lim (\frac{x ^{2} + 1}{x - 1})

y = \frac{- 8 x}{x ^{2} + 1}, (0, 0)

\int \frac{3}{t ^{4}} d t

What is the derivative of-3x^{-2} ?
The derivative of-3x^{-2} is 6/(x^3)
What is the first derivative of-3x^{-2} ?
The first derivative of-3x^{-2} is 6/(x^3)