What is the solution for (dy)/(dx)=(4/(x^2+1))(y+1) ?

The solution for (dy)/(dx)=(4/(x^2+1))(y+1) is y=e^{4arctan(x)+c_{1}}-1

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(dy)/(dx)=(4/(x^2+1))(y+1)

\frac{d y}{d x} = (\frac{4}{x ^{2} + 1}) (y + 1)

y = e^{4 a r c t a n (x) + c_{1}} - 1

Solution steps

\frac{d y}{d x} = (\frac{4}{x ^{2} + 1}) (y + 1)

Solve separable ODE:

y = e^{4 a r c t a n (x) + c_{1}} - 1

y = e^{4 a r c t a n (x) + c_{1}} - 1

y^{^{''}} + 4 y = e^{x}

φ^{3} cos (φ^{5})

\int \frac{1}{x ^{2} x ^{2} - 1} d x

f (x) = cos (8 x^{2} - 16) sin (x^{2})

(\frac{3}{5} x)^{5}

What is the solution for (dy)/(dx)=(4/(x^2+1))(y+1) ?
The solution for (dy)/(dx)=(4/(x^2+1))(y+1) is y=e^{4arctan(x)+c_{1}}-1