What is the derivative of 6+1/(x^2) ?

The derivative of 6+1/(x^2) is -2/(x^3)

What is the first derivative of 6+1/(x^2) ?

The first derivative of 6+1/(x^2) is -2/(x^3)

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derivative of

6 + \frac{1}{x ^{2}}

- \frac{2}{x ^{3}}

Solution steps

\frac{d}{d x} (6 + \frac{1}{x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6) + \frac{d}{d x} (\frac{1}{x ^{2}})

\frac{d}{d x} (6) = 0

\frac{d}{d x} (\frac{1}{x ^{2}}) = - \frac{2}{x ^{3}}

= 0 - \frac{2}{x ^{3}}

Simplify

= - \frac{2}{x ^{3}}

y^{^{''}} + 4 y = 3 cos (2 t) - 5 sin (2 t)

y = x^{4} - 4 x^{2} + 10, at x = 1

\frac{d}{d x} (e^{- x} cos (2 x))

\int_{0}^{1} \frac{x}{1 - x ^{2}} d x

\frac{x d y}{d x} = 5 x e^{x} - y + 6 x^{2}

What is the derivative of 6+1/(x^2) ?
The derivative of 6+1/(x^2) is -2/(x^3)
What is the first derivative of 6+1/(x^2) ?
The first derivative of 6+1/(x^2) is -2/(x^3)