What is the limit as x approaches 0+of 1/(1+1/x) ?

The limit as x approaches 0+of 1/(1+1/x) is 0

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limit as x approaches 0+of 1/(1+1/x)

x \to 0 + lim (\frac{1}{1 + \frac{1}{x}})

0

Solution steps

x \to 0 + lim (\frac{1}{1 + \frac{1}{x}})

x \to a lim [\frac{f ( x )}{g ( x )}] = \frac{lim _{x \to a} f ( x )}{lim _{x \to a} g ( x )}, x \to a lim g (x) \neq = 0

With the exception of indeterminate form

= \frac{lim _{x \to 0 +} ( 1 )}{lim _{x \to 0 +} ( 1 + \frac{1}{x} )}

x \to 0 + lim (1) = 1

x \to 0 + lim (1 + \frac{1}{x}) = \infty

= \frac{1}{\infty}

Apply Infinity Property:

\frac{c}{\infty} = 0

= 0

\frac{d}{d x} (- 8)

x \to 0 lim (\frac{sin ^{2} ( 3 x )}{5 x ^{2}})

\int sin (4 x) sin (x) d x

2 (t + 2)

\frac{d}{d x} (\frac{2 x}{x ^{6} + 3 x ^{2}})

What is the limit as x approaches 0+of 1/(1+1/x) ?
The limit as x approaches 0+of 1/(1+1/x) is 0