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Popular >

xy+y^'=2x,y(0)=5

Solution

x y + y^{^{'}} = 2 x, y (0) = 5

Solution

y = 3 e^{- \frac{x ^{2}}{2}} + 2

Solution steps

x y + y^{'} (x) = 2 x

Solve separable ODE:

y = 3 e^{- \frac{x ^{2}}{2}} + 2

y = 3 e^{- \frac{x ^{2}}{2}} + 2

Popular Examples

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\int 2 a 1 + cos (θ) d θ

derivative of cos(x-1/3 cos^3(x))

\frac{d}{d x} (cos (x) - \frac{1}{3} cos^{3} (x))

Frequently Asked Questions (FAQ)

What is the solution for xy+y^'=2x,y(0)=5 ?
The solution for xy+y^'=2x,y(0)=5 is y=3e^{-(x^2)/2}+2