What is the solution for y^3=(dy)/(dx)+y ?

The solution for y^3=(dy)/(dx)+y is y=sqrt(1/(-e^{2x+c_{1))+1}},y=-sqrt(1/(-e^{2x+c_{1))+1}}

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y^3=(dy)/(dx)+y

y^{3} = \frac{d y}{d x} + y

y = \frac{1}{- e ^{2 x + c_{1}} + 1}, y = - \frac{1}{- e ^{2 x + c_{1}} + 1}

Solution steps

y^{3} = \frac{d y}{d x} + y

Solve Bernoulli ODE:

y = \frac{1}{- e ^{2 x + c_{1}} + 1}, y = - \frac{1}{- e ^{2 x + c_{1}} + 1}

y = \frac{1}{- e ^{2 x + c_{1}} + 1}, y = - \frac{1}{- e ^{2 x + c_{1}} + 1}

\int_{- 8}^{8} (64 - x^{2}) d x

\frac{d}{d x} (\frac{- 2 x ^{2} + 1}{1 - x ^{2}})

\int \frac{1}{1 + 2 cos ( x )} d x

\frac{d}{d x} (\frac{x - 2}{x ^{2}})

y = 4 2 x, y = 2 x^{2}, y = - 4 x + 6

What is the solution for y^3=(dy)/(dx)+y ?
The solution for y^3=(dy)/(dx)+y is y=sqrt(1/(-e^{2x+c_{1))+1}},y=-sqrt(1/(-e^{2x+c_{1))+1}}