What is the derivative of sin(x^2+y^2) ?

The derivative of sin(x^2+y^2) is cos(x^2+y^2)(2x+2y(dy)/(dx))

What is the first derivative of sin(x^2+y^2) ?

The first derivative of sin(x^2+y^2) is cos(x^2+y^2)(2x+2y(dy)/(dx))

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\frac{d}{d x} (sin (x^{2} + y^{2}))

cos (x^{2} + y^{2}) (2 x + 2 y \frac{d y}{d x})

Solution steps

\frac{d}{d x} (sin (x^{2} + y^{2}))

Apply the chain rule:

cos (x^{2} + y^{2}) \frac{d}{d x} (x^{2} + y^{2})

= cos (x^{2} + y^{2}) \frac{d}{d x} (x^{2} + y^{2})

\frac{d}{d x} (x^{2} + y^{2}) = 2 x + 2 y \frac{d y}{d x}

= cos (x^{2} + y^{2}) (2 x + 2 y \frac{d y}{d x})

y^{2} = 4 x, x = 1, x = 4

x \to 0 - lim (2 + \frac{3}{x})

\frac{d y}{d t} - 4 y = 10 sin (2 t), y (0) = 0

\frac{d}{d x} (e^{arccsc (x)})

\frac{d}{d x} (- a sin (x) + b cos (x))

What is the derivative of sin(x^2+y^2) ?
The derivative of sin(x^2+y^2) is cos(x^2+y^2)(2x+2y(dy)/(dx))
What is the first derivative of sin(x^2+y^2) ?
The first derivative of sin(x^2+y^2) is cos(x^2+y^2)(2x+2y(dy)/(dx))