What is the derivative of A/(y^7)+Be^y ?

The derivative of A/(y^7)+Be^y is -(7A)/(y^8)+Be^y

What is the first derivative of A/(y^7)+Be^y ?

The first derivative of A/(y^7)+Be^y is -(7A)/(y^8)+Be^y

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derivative of

\frac{A}{y ^{7}} + B e^{y}

- \frac{7 A}{y ^{8}} + B e^{y}

Solution steps

\frac{d}{d y} (\frac{A}{y ^{7}} + B e^{y})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (\frac{A}{y ^{7}}) + \frac{d}{d y} (B e^{y})

\frac{d}{d y} (\frac{A}{y ^{7}}) = - \frac{7 A}{y ^{8}}

\frac{d}{d y} (B e^{y}) = B e^{y}

= - \frac{7 A}{y ^{8}} + B e^{y}

n = 1 \sum \infty \frac{3 - 2 n}{4 n}

(- 2, 7), (2, 3)

\int sin^{4} (a x) d x

\frac{d}{d x} (10 x e^{- 2 x})

y = x^{2} - 4, y = 3 x

What is the derivative of A/(y^7)+Be^y ?
The derivative of A/(y^7)+Be^y is -(7A)/(y^8)+Be^y
What is the first derivative of A/(y^7)+Be^y ?
The first derivative of A/(y^7)+Be^y is -(7A)/(y^8)+Be^y