What is the solution for y^{''}-2xy^'=0 ?

The solution for y^{''}-2xy^'=0 is y=c_{1}(sqrt(pi))/2 \erfi(x)+c_{2}

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y^{''}-2xy^'=0

y^{^{''}} - 2 x y^{^{'}} = 0

y = c_{1} \frac{π}{2} erfi (x) + c_{2}

Solution steps

y^{''} (x) - 2 x y^{'} (x) = 0

Solve using substitution:

y = c_{1} \frac{π}{2} erfi (x) + c_{2}

y = c_{1} \frac{π}{2} erfi (x) + c_{2}

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What is the solution for y^{''}-2xy^'=0 ?
The solution for y^{''}-2xy^'=0 is y=c_{1}(sqrt(pi))/2 \erfi(x)+c_{2}