What is the integral of 1/(4x) ?

The integral of 1/(4x) is 1/4 ln|x|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(4x)

\int \frac{1}{4 x} d x

\frac{1}{4} ln ∣ x ∣ + C

Solution steps

\int \frac{1}{4 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= \frac{1}{4} ln ∣ x ∣

Add a constant to the solution

= \frac{1}{4} ln ∣ x ∣ + C

\frac{d}{d x} (4 x^{3} + 5 x)

\frac{d}{d x} (arctan (\frac{5}{x}))

\frac{x ^{2} + 2 x - 2}{( x + 1 ) ^{2}}

\frac{\partial}{\partial z} (x z e^{yz})

y^{^{'}} = 0.23 y - 0.0005 y^{2}