What is the integral from 1 to 10 of 1/(x^2) ?

The integral from 1 to 10 of 1/(x^2) is 9/10

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integral from 1 to 10 of 1/(x^2)

\int_{1}^{10} \frac{1}{x ^{2}} d x

\frac{9}{10}

Decimal Notation

0.9

Solution steps

\int_{1}^{10} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{10}

= [- \frac{1}{x}]_{1}^{10}

Compute the boundaries:

\frac{9}{10}

= \frac{9}{10}

x^{2} (sin (x))

\frac{d y}{d x} = y \cdot (\frac{1}{x} - y)

\frac{\partial}{\partial u} (\frac{v}{u})

\frac{d}{d x} (ln (\frac{9 - x}{5 + x}))

- 9 x^{2}

What is the integral from 1 to 10 of 1/(x^2) ?
The integral from 1 to 10 of 1/(x^2) is 9/10