What is the solution for (dy)/(dx)=((x-3))/(y-4) ?

The solution for (dy)/(dx)=((x-3))/(y-4) is y=4+sqrt(x^2-6x+c_{1)+16},y=4-sqrt(x^2-6x+c_{1)+16}

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(dy)/(dx)=((x-3))/(y-4)

\frac{d y}{d x} = \frac{( x - 3 )}{y - 4}

y = 4 + x^{2} - 6 x + c_{1} + 16, y = 4 - x^{2} - 6 x + c_{1} + 16

Solution steps

\frac{d y}{d x} = \frac{( x - 3 )}{y - 4}

Solve separable ODE:

y = 4 + x^{2} - 6 x + c_{1} + 16, y = 4 - x^{2} - 6 x + c_{1} + 16

y = 4 + x^{2} - 6 x + c_{1} + 16, y = 4 - x^{2} - 6 x + c_{1} + 16

\int \frac{289}{x ^{3} - 17 x ^{2}} d x

\int (1 - t) d t

x \to 0 + lim (I n x)

\int - \frac{1}{x - 1} d x

\int_{3}^{x^{3}} t^{3} d t

What is the solution for (dy)/(dx)=((x-3))/(y-4) ?
The solution for (dy)/(dx)=((x-3))/(y-4) is y=4+sqrt(x^2-6x+c_{1)+16},y=4-sqrt(x^2-6x+c_{1)+16}