What is the tangent of 22x^3 ?

The tangent of 22x^3 is y=66a_{0}^2x-44a_{0}^3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 22x^3

tangent of

22 x^{3}

y = 66 a_{0}^{2} x - 44 a_{0}^{3}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 22 a_{0}^{3})

Find the slope of

y = 22 x^{3} : \frac{d y}{d x} = 66 x^{2}

Compute the slope of

y = 22 x^{3}

x = a_{0} : m = 66 a_{0}^{2}

Find the line with slope m=

66 a_{0}^{2}

and passing through

(a_{0}, 22 a_{0}^{3}) : y = 66 a_{0}^{2} x - 44 a_{0}^{3}

y = 66 a_{0}^{2} x - 44 a_{0}^{3}

\frac{\partial}{\partial x} (y + (cos^{2} (x)))

x \to 2 lim (sin (x))

\frac{d}{d x} (sin^{2} (e^{3 x + 1}))

n = 0 \sum \infty \frac{3 ^{n}}{3 ^{n}}

\int \frac{x ^{3}}{x ^{4} - 3} d x