What is the tangent of 9x-9sqrt(x) ?

The tangent of 9x-9sqrt(x) is y=(9-9/(2sqrt(a_{0))})x-9sqrt(a_{0)}+(9sqrt(a_{0)})/2

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tangent of 9x-9sqrt(x)

tangent of

9 x - 9 x

y = (9 - \frac{9}{2 a _{0}}) x - 9 a_{0} + \frac{9 a _{0}}{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 9 a_{0} - 9 a_{0})

Find the slope of

y = 9 x - 9 x : \frac{d y}{d x} = 9 - \frac{9}{2 x}

Compute the slope of

y = 9 x - 9 x

x = a_{0} : m = 9 - \frac{9}{2 a _{0}}

Find the line with slope m=

9 - \frac{9}{2 a _{0}}

and passing through

(a_{0}, 9 a_{0} - 9 a_{0}) : y = (9 - \frac{9}{2 a _{0}}) x - 9 a_{0} + \frac{9 a _{0}}{2}

y = (9 - \frac{9}{2 a _{0}}) x - 9 a_{0} + \frac{9 a _{0}}{2}

\frac{d}{d x} ((x^{2} + y^{2}) sin (\frac{1}{x ^{2} + y ^{2}}))

\int sin (x) in (cos (x)) d x

f (x) = 8 sec (x) tan (x)

f (x) = x^{2} + 1, (0, 1)

n = 5 \sum \infty \frac{3 ^{n}}{1 2 ^{n}}

What is the tangent of 9x-9sqrt(x) ?
The tangent of 9x-9sqrt(x) is y=(9-9/(2sqrt(a_{0))})x-9sqrt(a_{0)}+(9sqrt(a_{0)})/2