What is (\partial)/(\partial x)(sqrt(6-2x^2+3y^2)) ?

The answer to (\partial)/(\partial x)(sqrt(6-2x^2+3y^2)) is -(2x)/(sqrt(6-2x^2+3y^2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(sqrt(6-2x^2+3y^2))

\frac{\partial}{\partial x} (6 - 2 x^{2} + 3 y^{2})

- \frac{2 x}{6 - 2 x ^{2} + 3 y ^{2}}

Solution steps

\frac{\partial}{\partial x} (6 - 2 x^{2} + 3 y^{2})

Treat

y

as a constant

Apply the chain rule:

\frac{1}{2 6 - 2 x ^{2} + 3 y ^{2}} \frac{\partial}{\partial x} (6 - 2 x^{2} + 3 y^{2})

= \frac{1}{2 6 - 2 x ^{2} + 3 y ^{2}} \frac{\partial}{\partial x} (6 - 2 x^{2} + 3 y^{2})

\frac{\partial}{\partial x} (6 - 2 x^{2} + 3 y^{2}) = - 4 x

= \frac{1}{2 6 - 2 x ^{2} + 3 y ^{2}} (- 4 x)

Simplify

\frac{1}{2 6 - 2 x ^{2} + 3 y ^{2}} (- 4 x) : - \frac{2 x}{6 - 2 x ^{2} + 3 y ^{2}}

= - \frac{2 x}{6 - 2 x ^{2} + 3 y ^{2}}

f (x) = x^{\frac{1}{2}}, (81, 9)

\int \frac{ln ( x )}{5 x ^{4}} d x

\int 4 - r^{2} d r

h \to 0 lim (\frac{( h - 3 ) ^{3} + 1}{h})

f (x) = lo g_{2} (1 - 3 x)

What is (\partial)/(\partial x)(sqrt(6-2x^2+3y^2)) ?
The answer to (\partial)/(\partial x)(sqrt(6-2x^2+3y^2)) is -(2x)/(sqrt(6-2x^2+3y^2))