What is the derivative of 9xsin(x) ?

The derivative of 9xsin(x) is 9(sin(x)+xcos(x))

What is the first derivative of 9xsin(x) ?

The first derivative of 9xsin(x) is 9(sin(x)+xcos(x))

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\frac{d}{d x} (9 x sin (x))

9 (sin (x) + x cos (x))

Solution steps

\frac{d}{d x} (9 x sin (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (x sin (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = sin (x)

= 9 (\frac{d x}{d x} sin (x) + \frac{d}{d x} (sin (x)) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (sin (x)) = cos (x)

= 9 (1 \cdot sin (x) + cos (x) x)

Simplify

= 9 (sin (x) + x cos (x))

\frac{d}{d x} (\frac{4}{3} π^{3})

\int \frac{5 z ^{2}}{y} d y

lo g_{5} (x^{4})

\frac{\partial}{\partial y} (x - 1)

\frac{\partial}{\partial x} ((2 x - 3 y)^{3})

What is the derivative of 9xsin(x) ?
The derivative of 9xsin(x) is 9(sin(x)+xcos(x))
What is the first derivative of 9xsin(x) ?
The first derivative of 9xsin(x) is 9(sin(x)+xcos(x))