What is the solution for y'=0.0015y(2100-y) ?

The solution for y'=0.0015y(2100-y) is y=(3.15)/(-e^{-3.15t-c_{1)}+0.0015}

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y'=0.0015y(2100-y)

y^{^{'}} = 0.0015 y (2100 - y)

y = \frac{3.15}{- e ^{- 3.15 t - c_{1}} + 0.0015}

Solution steps

y^{'} (t) = 0.0015 y (2100 - y)

Solve Bernoulli ODE:

y = \frac{3.15}{- e ^{- 3.15 t - c_{1}} + 0.0015}

y = \frac{3.15}{- e ^{- 3.15 t - c_{1}} + 0.0015}

\frac{d y}{d x} = x^{\frac{3}{2}}

\int - \frac{1}{n ^{2}} cos (n t) d t

\frac{\partial}{\partial x} (x^{3} cos (x y))

x = y^{2}, x = 6 - 2 y^{2}

\int (9 x 1 + 2 x^{2}) d x

What is the solution for y'=0.0015y(2100-y) ?
The solution for y'=0.0015y(2100-y) is y=(3.15)/(-e^{-3.15t-c_{1)}+0.0015}