What is (\partial)/(\partial x)(7sec(x)-4x) ?

The answer to (\partial)/(\partial x)(7sec(x)-4x) is 7sec(x)tan(x)-4

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(\partial)/(\partial x)(7sec(x)-4x)

\frac{\partial}{\partial x} (7 sec (x) - 4 x)

7 sec (x) tan (x) - 4

Solution steps

\frac{\partial}{\partial x} (7 sec (x) - 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (7 sec (x)) - \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (7 sec (x)) = 7 sec (x) tan (x)

\frac{\partial}{\partial x} (4 x) = 4

= 7 sec (x) tan (x) - 4

y^{^{'}} = \frac{4 x ^{2} + 3 y ^{2}}{2 x y}

x^{2} - 8, - x^{2} + 2 x + 4

\frac{d}{d x} (ln (\frac{2 - x}{1 - x}))

\frac{d y}{d x} = \frac{( 1 + x )}{x y ^{16}}

\int (2 x - 40) \cdot ln (x - 20) d x

What is (\partial)/(\partial x)(7sec(x)-4x) ?
The answer to (\partial)/(\partial x)(7sec(x)-4x) is 7sec(x)tan(x)-4