What is the integral of 4x^3+9x^2y^2+3 ?

The integral of 4x^3+9x^2y^2+3 is 3x+x^4+3y^2x^3+C

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integral of 4x^3+9x^2y^2+3

\int 4 x^{3} + 9 x^{2} y^{2} + 3 d x

3 x + x^{4} + 3 y^{2} x^{3} + C

Solution steps

\int 4 x^{3} + 9 x^{2} y^{2} + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 d x + \int 4 x^{3} d x + \int 9 y^{2} x^{2} d x

\int 3 d x = 3 x

\int 4 x^{3} d x = x^{4}

\int 9 y^{2} x^{2} d x = 3 y^{2} x^{3}

= 3 x + x^{4} + 3 y^{2} x^{3}

Add a constant to the solution

= 3 x + x^{4} + 3 y^{2} x^{3} + C

n = 1 \sum \infty 7 - 6 (0.8)^{n}

\int 5 sin (2 x) d x

\int (1.3)^{x} d x

\int e^{2 x} + 1 d x

x \to 0 + lim (tan^{x} (4 x))

What is the integral of 4x^3+9x^2y^2+3 ?
The integral of 4x^3+9x^2y^2+3 is 3x+x^4+3y^2x^3+C