What is the integral of 3/(\sqrt[3]{x)} ?

The integral of 3/(\sqrt[3]{x)} is 9/2 x^{2/3}+C

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integral of 3/(\sqrt[3]{x)}

\frac{9}{2} x^{\frac{2}{3}} + C

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply the Power Rule

: \frac{3}{2} x^{\frac{2}{3}}

= 3 \cdot \frac{3}{2} x^{\frac{2}{3}}

Simplify

3 \cdot \frac{3}{2} x^{\frac{2}{3}} : \frac{9}{2} x^{\frac{2}{3}}

= \frac{9}{2} x^{\frac{2}{3}}

Add a constant to the solution

= \frac{9}{2} x^{\frac{2}{3}} + C

\frac{d}{d t} (- 3 e^{- 3 t})

4 sin (x + \frac{π}{3}) - 1

\frac{\partial}{\partial y} (1 + 2 x y)

1 - e^{3 x^{2}}

What is the integral of 3/(\sqrt[3]{x)} ?
The integral of 3/(\sqrt[3]{x)} is 9/2 x^{2/3}+C